(D) The power or rate of heat production is given by $P = VI$.Given $V = 60 \ kV = 60 \times 10^3 \ V$ and $I = 50 \ mA = 50 \times 10^{-3} \ A$.$P =

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(D) The power or rate of heat production is given by $P = VI$.Given $V = 60 \ kV = 60 \times 10^3 \ V$ and $I = 50 \ mA = 50 \times 10^{-3} \ A$.$P = (60 \times 10^3) \times (50 \times 10^{-3}) = 3000 \ J/s$.Since $1 \ calorie = 4.2 \ J$,the rate of heat production in $cal/s$ is $\frac{3000}{4.2} \ cal/s$.$P \approx 714.3 \ cal/s$.Thus,the correct option is $D$.

Class 12 Physics Atoms X-Rays

Medium

When an $X$-ray tube operates at $60 \ kV$,the observed tube current is $50 \ mA$. Assuming that the total energy of the electrons is converted into heat,the rate of heat production at the anode in $cal/s$ is:

A
$100$
B
$300$
C
$500$
D
$714$

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X-Rays

How are $X$-rays produced in the laboratory?

Medium

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If ${\lambda _1}$ and ${\lambda _2}$ are the wavelengths of characteristic $X$-rays and gamma rays respectively,then the relation between them is

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If $V$ is the accelerating voltage,then the maximum frequency of continuous $X$-rays is given by

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The essential distinction between $X$-rays and $\gamma$-rays is that:

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The graph that correctly represents the relation of frequency $\nu$ of a particular characteristic $X$-ray with the atomic number $Z$ of the material is

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When an $X$-ray tube operates at $60 \ kV$,the observed tube current is $50 \ mA$. Assuming that the total energy of the electrons is converted into heat,the rate of heat production at the anode in $cal/s$ is:

Similar Questions

How are $X$-rays produced in the laboratory?

If ${\lambda _1}$ and ${\lambda _2}$ are the wavelengths of characteristic $X$-rays and gamma rays respectively,then the relation between them is

If $V$ is the accelerating voltage,then the maximum frequency of continuous $X$-rays is given by

The essential distinction between $X$-rays and $\gamma$-rays is that:

The graph that correctly represents the relation of frequency $\nu$ of a particular characteristic $X$-ray with the atomic number $Z$ of the material is

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