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(D) The ice point on the Celsius scale is $0^{\circ} C$ and the steam point is $100^{\circ} C$. In the new scale,the ice point is $25 X$ and the steam

Vedclass · Accepted Answer

$1.5 	imes 10^{3}$

Vedclass · Answer

(D) The ice point on the Celsius scale is $0^{\circ} C$ and the steam point is $100^{\circ} C$. In the new scale,the ice point is $25 X$ and the steam point is $305 X$. The temperature interval of $100^{\circ} C$ corresponds to $(305 - 25) X = 280 X$. Therefore,a change of $1^{\circ} C$ is equivalent to a change of $\frac{280}{100} X = 2.8 X$. This implies $1^{\circ} C = 2.8 X$,or $1 X = \frac{1}{2.8}^{\circ} C$. The specific heat capacity of water is $c = 4200 \ J kg^{-1} (^{\circ} C)^{-1}$. Substituting the relation $1^{\circ} C = 2.8 X$ into the unit: $c = 4200 \ J kg^{-1} (2.8 X)^{-1} = \frac{4200}{2.8} J kg^{-1} X^{-1} = 1500 \ J kg^{-1} X^{-1}$. Thus,$c = 1.5 	imes 10^{3} J kg^{-1} X^{-1}$.

$A$ scientist proposes a new temperature scale in which the ice point is $25 X$ ($X$ is the new unit of temperature) and the steam point is $305 X$. The specific heat capacity of water in this new scale is (in $J kg^{-1} X^{-1}$):

Similar Questions

$A$ thermometer graduated according to a linear scale reads a value $x_0$ when in contact with boiling water,and $x_0/3$ when in contact with ice. What is the temperature of an object in ${}^oC$,if this thermometer in contact with the object reads $x_0/2$?

Assertion $(A)$: Rapidly changing temperatures can be measured by thermocouples.
Reason $(R)$: The thermal capacity of the junction of a thermocouple is very small.

The graph $AB$ shown in the figure is a plot of the temperature of a body in degree Celsius $(C)$ versus degree Fahrenheit $(F)$. Then:

The temperature at which the reading on the Fahrenheit scale becomes $90 \%$ more than the reading on the Celsius scale is: (in $^{\circ} F$)

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