mathop {lim }limits_{x to 0} frac{{2{{sin }^2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) हम जानते हैं कि $\mathop {\lim }\limits_{	heta 	o 0} \frac{{\sin 	heta }}{	heta } = 1$. दिया गया व्यंजक $\mathop {\lim }\limits_{x 	o 0} \fra

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(C) हम जानते हैं कि $\mathop {\lim }\limits_{	heta 	o 0} \frac{{\sin 	heta }}{	heta } = 1$. दिया गया व्यंजक $\mathop {\lim }\limits_{x 	o 0} \frac{{2{{\sin }^2}3x}}{{{x^2}}}$ है। $= 2 	imes \mathop {\lim }\limits_{x 	o 0} \left( \frac{{\sin 3x}}{x} ight)^2$. $= 2 	imes \mathop {\lim }\limits_{x 	o 0} \left( 3 	imes \frac{{\sin 3x}}{{3x}} ight)^2$. $= 2 	imes 3^2 	imes \left( \mathop {\lim }\limits_{3x 	o 0} \frac{{\sin 3x}}{{3x}} ight)^2$. $= 2 	imes 9 	imes (1)^2 = 18$.

$\mathop {\lim }\limits_{x \to 0} \frac{{2{{\sin }^2}3x}}{{{x^2}}} = $

Similar Questions

$\lim _{x \rightarrow 0} \frac{\tan ^3 x - \sin ^3 x}{x^5}$ का मान ज्ञात कीजिए।

$\lim _{x \rightarrow 0} \left( \frac{\sin (\pi \cos ^2 x)}{x^2} \right) = $

$\lim _{x \rightarrow 0} \frac{\cos 7 x^{\circ}-\cos 2 x^{\circ}}{x^2}$ का मान ज्ञात कीजिए।

$\lim _{x \rightarrow 0} \frac{(1-\cos 2 x)(3+\cos x)}{x \tan 4 x} = $

$\mathop {\lim }\limits_{x \to 0} \left( {\frac{{\tan 3x}}{x} + \cos x} \right) = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module