(A) Elevation in boiling point is given by $\Delta T_{b} = i \times K_{b} \times m$. For $NaCl$ $(58.4 \ g \approx 1 \text{ mole})$,$i = 2$. For gluco

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$NaCl$ solution will show higher elevation of boiling point

(A) Elevation in boiling point is given by $\Delta T_{b} = i \times K_{b} \times m$. For $NaCl$ $(58.4 \ g \approx 1 \text{ mole})$,$i = 2$. For glucose $(180 \ g = 1 \text{ mole})$,$i = 1$. Since both solutes are dissolved in the same amount of solvent ($1000 \ mL \approx 1 \text{ kg}$ of water),their molality $(m)$ is the same. Therefore,$\Delta T_{b} \propto i$. Since $i_{NaCl} > i_{glucose}$,the $NaCl$ solution will show a higher elevation of boiling point.

Class 12 Chemistry Solutions Elevation of boiling point of the solvent

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$58.4 \ g$ of $NaCl$ and $180 \ g$ of glucose were separately dissolved in $1000 \ mL$ of water. Identify the correct statement regarding the elevation of boiling point $(b.p.)$ of the resulting solutions.

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A
$NaCl$ solution will show higher elevation of boiling point
B
Glucose solution will show higher elevation of boiling point
C
Both the solutions will show equal elevation of boiling point
D
The boiling point elevation will be shown by neither of the solutions

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Elevation of boiling point of the solvent

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Pure benzene boils at $80\,^oC$. When $1\,g$ of a solute is dissolved in $83.4\,g$ of benzene,the boiling point of the solution becomes $80.175\,^oC$. If the latent heat of vaporization of benzene is $90\,cal/g$,calculate the molar mass of the solute.

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If $10 \ g$ of a solute (molar mass $= 100 \ g/mol$) is dissolved in $100 \ g$ of water,then the molal elevation constant $K_b$ of the solvent will be equal to:

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Which of the following equations correctly represents the molar mass of a solute by knowing the boiling point elevation?

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When a substance is dissolved in a solvent,the vapour pressure of the solvent is decreased. This results in:

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What is elevation in boiling point? Explain.

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$58.4 \ g$ of $NaCl$ and $180 \ g$ of glucose were separately dissolved in $1000 \ mL$ of water. Identify the correct statement regarding the elevation of boiling point $(b.p.)$ of the resulting solutions.

Similar Questions

Pure benzene boils at $80\,^oC$. When $1\,g$ of a solute is dissolved in $83.4\,g$ of benzene,the boiling point of the solution becomes $80.175\,^oC$. If the latent heat of vaporization of benzene is $90\,cal/g$,calculate the molar mass of the solute.

If $10 \ g$ of a solute (molar mass $= 100 \ g/mol$) is dissolved in $100 \ g$ of water,then the molal elevation constant $K_b$ of the solvent will be equal to:

Which of the following equations correctly represents the molar mass of a solute by knowing the boiling point elevation?

When a substance is dissolved in a solvent,the vapour pressure of the solvent is decreased. This results in:

What is elevation in boiling point? Explain.

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