$A$ car travelling at a speed of $54 \ km/h$ towards a wall sounds a horn of frequency $400 \ Hz$. The difference in the frequencies of two sounds,one received directly from the car and the other reflected from the wall,noticed by a person standing between the car and the wall is (speed of sound in air is $335 \ m/s$):

  • A
    $35.9 \ Hz$
  • B
    $20 \ Hz$
  • C
    $70 \ Hz$
  • D
    $35.9 \ Hz$ (Wait,let's calculate: $v_s = 54 \ km/h = 15 \ m/s$,$v = 335 \ m/s$,$f = 400 \ Hz$. Direct sound frequency $f_1 = f = 400 \ Hz$. Reflected sound frequency $f_2 = f \times \frac{v}{v - v_s} = 400 \times \frac{335}{335 - 15} = 400 \times \frac{335}{320} = 418.75 \ Hz$. Difference $= 418.75 - 400 = 18.75 \ Hz$. Since $18.75 \ Hz$ is not in options,let's re-evaluate. If the observer is between the car and wall,the direct sound is $f_1 = f \times \frac{v}{v - v_s}$ and reflected is $f_2 = f \times \frac{v}{v - v_s}$. The difference is zero. Wait,the observer is stationary. Direct sound $f_1 = f \times \frac{v}{v - v_s}$. Reflected sound $f_2 = f \times \frac{v}{v - v_s}$. The difference is $0$. Let's re-read: 'person standing between the car and the wall'. The car is moving towards the wall. The person hears direct sound from the car (source moving towards observer) and reflected sound from the wall (wall acts as a source moving towards observer). Both frequencies are the same. Difference is Zero.

Explore More

Similar Questions

When both source and listener are approaching each other,the observed frequency of sound is given by (where $V$ is the speed of sound,$V_L$ and $V_S$ are the velocities of the listener and source respectively,and $n_0$ is the radiated frequency):

The velocity of sound is $340 \,m/s$. $A$ source of sound having a frequency of $90 \,Hz$ is moving towards a stationary observer with a speed of one-tenth that of sound. The apparent frequency of sound as heard by the observer is: (in $\,Hz$)

$Assertion :$ The Doppler formula for sound waves is symmetric with respect to the speed of the source and the speed of the observer.
$Reason :$ The motion of a source with respect to a stationary observer is not equivalent to the motion of an observer with respect to a stationary source.

$A$ siren emitting a sound of frequency $800 \, Hz$ moves away from an observer towards a cliff at a speed of $15 \, m s^{-1}$. The frequency of sound that the observer hears in the echo reflected from the cliff is .... $Hz$ (Take velocity of sound in air $= 330 \, m s^{-1}$)

$A$ stationary source emits sound waves of frequency $500\, Hz$. Two observers moving along a line passing through the source detect sound to be of frequencies $480\, Hz$ and $530\, Hz$. Their respective speeds are,in $m\,s^{-1}$ (Given speed of sound $= 300\, m/s$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo