Medium
$A$ man of mass $80 \ kg$ goes to the market on a scooter of mass $100 \ kg$ with a certain speed. On application of brakes,the stopping distance is $S_1$. The man returns home on the same scooter,with the same speed with a $60 \ kg$ bag of rice. If $S_2$ is the new stopping distance when the brakes are applied with the same force,then:
- A$7 S_1 = 4 S_2$
- B$2 S_1 = S_2$
- C$3 S_1 = 4 S_2$
- D$4 S_1 = 3 S_2$
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