A horizontal pipeline carrying gasoline has a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given: Diameter of pipe $d = 5 \,mm = 5 	imes 10^{-3} \,m$. Density of gasoline $ho = 720 \,kg/m^3$. Viscosity of gasoline $\eta = 6 	imes 10^

Vedclass · Accepted Answer

$ > 0.33 \,m/s$

Vedclass · Answer

(D) Given: Diameter of pipe $d = 5 \,mm = 5 	imes 10^{-3} \,m$. Density of gasoline $ho = 720 \,kg/m^3$. Viscosity of gasoline $\eta = 6 	imes 10^{-3} \,Poise = 6 	imes 10^{-4} \,Pa \cdot s$. The critical Reynolds number for pipe flow is $R_e = 2000$. The formula for critical velocity $v_c$ is $v_c = \frac{R_e \cdot \eta}{ho \cdot d}$. Substituting the values: $v_c = \frac{2000 	imes 6 	imes 10^{-4}}{720 	imes 5 	imes 10^{-3}} = \frac{1.2}{3.6} = \frac{1}{3} \approx 0.33 \,m/s$. Thus,the flow becomes turbulent when the velocity is $ > 0.33 \,m/s$.

$A$ horizontal pipeline carrying gasoline has a cross-sectional diameter of $5 \,mm$. If the viscosity and density of the gasoline are $6 \times 10^{-3} \,Poise$ and $720 \,kg/m^3$ respectively,the velocity after which the flow becomes turbulent is:

Similar Questions

What is the value of Reynolds number for unsteady flow?

Water flows from a tap of diameter $1.5 \ cm$ with a flow rate of $7.5 \times 10^{-5} \ m^3 \ s^{-1}$. The coefficient of viscosity of water is $10^{-3} \ Pa \cdot s$. The flow is:

Explain Reynolds Number.

Two capillary tubes of the same radius but lengths $l_1$ and $l_2$ are connected in parallel at the bottom of a vessel. What should be the length of a single capillary tube of the same radius that replaces both,such that the flow rate remains the same?

Two different liquids are flowing in two tubes of equal radius. The ratio of coefficients of viscosity of liquids is $52:49$ and the ratio of their densities is $13:1$,then the ratio of their critical velocities will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module