A current-carrying conductor obeys Ohm's law | vedclass

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(C) Given,current passing through the conductor,$I = (5 \pm 0.2) 	ext{ A}$,where $\Delta I = 0.2 	ext{ A}$.Voltage developed,$V = (60 \pm 6) 	ext{

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(C) Given,current passing through the conductor,$I = (5 \pm 0.2) 	ext{ A}$,where $\Delta I = 0.2 	ext{ A}$.Voltage developed,$V = (60 \pm 6) 	ext{ V}$,where $\Delta V = 6 	ext{ V}$.By Ohm's law,$V = RI$,so $R = V/I$.The relative error in resistance $R$ is given by the formula: $\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$.Substituting the given values: $\frac{\Delta R}{R} = \frac{6}{60} + \frac{0.2}{5}$.Calculating the terms: $\frac{\Delta R}{R} = 0.1 + 0.04 = 0.14$.To find the percentage error,multiply by $100$: $\frac{\Delta R}{R} 	imes 100 = 0.14 	imes 100 = 14\%$.

$A$ current-carrying conductor obeys Ohm's law $(V = RI)$. If the current passing through the conductor is $I = (5 \pm 0.2) \text{ A}$ and the voltage developed is $V = (60 \pm 6) \text{ V}$,then find the percentage error in resistance $R$.

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