A 20 text{ ton} truck is travelling along a c | vedclass

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(D) To prevent the truck from toppling, the torque due to the centrifugal force about the outer wheels must not exceed the torque due to the weight of

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) To prevent the truck from toppling, the torque due to the centrifugal force about the outer wheels must not exceed the torque due to the weight of the truck about the same point.Let $V_{\max}$ be the maximum speed.The condition for the truck not to topple is given by the balance of torques: $\frac{m V_{\max}^2}{R} 	imes h = m g 	imes \frac{d}{2}$.Here, $h = 2 	ext{ m}$ (height of center of gravity), $R = 240 	ext{ m}$ (radius of path), and $d = 1.5 	ext{ m}$ (distance between wheels).Rearranging for $V_{\max}^2$: $V_{\max}^2 = \frac{g 	imes R 	imes d}{2 	imes h}$.Substituting the values: $V_{\max}^2 = \frac{10 	imes 240 	imes 1.5}{2 	imes 2}$.$V_{\max}^2 = \frac{3600}{4} = 900$.$V_{\max} = \sqrt{900} = 30 	ext{ ms}^{-1}$.

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