frac{1-cos 2 theta+sin 2 theta}{1+cos 2 theta | vedclass

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Question

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.S

Vedclass · Accepted Answer

$	an 	heta$

Vedclass · Answer

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.Substituting these into the expression:$\frac{1 - (1 - 2 \sin^2 	heta) + 2 \sin 	heta \cos 	heta}{1 + (2 \cos^2 	heta - 1) + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin^2 	heta + 2 \sin 	heta \cos 	heta}{2 \cos^2 	heta + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin 	heta (\sin 	heta + \cos 	heta)}{2 \cos 	heta (\cos 	heta + \sin 	heta)}$$= \frac{\sin 	heta}{\cos 	heta} = 	an 	heta$.

$\frac{1-\cos 2 \theta+\sin 2 \theta}{1+\cos 2 \theta+\sin 2 \theta}=$

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