$A$ current of $6 A$ is flowing at $220 V$ in the primary coil of a transformer. If the voltage produced in the secondary coil is $1100 V$ and $40 \%$ of power is lost, then the current in the secondary coil will be: (in $A$)

  • A
    $0.28$
  • B
    $0.36$
  • C
    $0.48$
  • D
    $0.42$

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