A distribution transformer with an efficiency | vedclass

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(B) The power consumed by $10$ ovens is given by $P = 10 	imes V 	imes I$.Given $V = 220 \ V$ and $I = 20 \ A$,we have:$P = 10 	imes 220 	imes 20

Vedclass · Accepted Answer

$4.9$

Vedclass · Answer

(B) The power consumed by $10$ ovens is given by $P = 10 	imes V 	imes I$.Given $V = 220 \ V$ and $I = 20 \ A$,we have:$P = 10 	imes 220 	imes 20 = 44,000 \ W = 44 \ kW$.Let $P'$ be the input power to the transformer. Since the efficiency $\eta = 90 \% = 0.9$,we have $P = \eta 	imes P'$.$P' = \frac{P}{0.9} = \frac{44 \ kW}{0.9} \approx 48.89 \ kW$.The power dissipated as heat in the transformer is $H = P' - P$.$H = 48.89 \ kW - 44 \ kW = 4.89 \ kW$.Rounding to the nearest option,$H \approx 4.9 \ kW$.

$A$ distribution transformer with an efficiency of $90 \%$ supplies power to a colony of $10$ homes. All the $10$ homes have an electrical oven running at the same time,each drawing $20 \ A$ current from $220 \ V$ lines. The power dissipated as heat in the transformer is: (in $kW$)

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