A black body of mass 34.38 g and surface are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The rate of cooling of a body is given by the formula: $\frac{d	heta}{dt} = \frac{\sigma A(T^4 - T_0^4)}{ms}$.Here,$m = 34.38 	imes 10^{-3} \ kg

Vedclass · Accepted Answer

$1400$

Vedclass · Answer

(C) The rate of cooling of a body is given by the formula: $\frac{d	heta}{dt} = \frac{\sigma A(T^4 - T_0^4)}{ms}$.Here,$m = 34.38 	imes 10^{-3} \ kg$,$A = 19.2 	imes 10^{-4} \ m^2$,$T = 400 \ K$,$T_0 = 300 \ K$,and $\frac{d	heta}{dt} = 0.04 \ K/s$.Rearranging for specific heat $s$: $s = \frac{\sigma A(T^4 - T_0^4)}{m(\frac{d	heta}{dt})}$.Substituting the values:$s = \frac{(5.73 	imes 10^{-8}) 	imes (19.2 	imes 10^{-4}) 	imes (400^4 - 300^4)}{(34.38 	imes 10^{-3}) 	imes 0.04}$.$s = \frac{(5.73 	imes 10^{-8}) 	imes (19.2 	imes 10^{-4}) 	imes (256 	imes 10^8 - 81 	imes 10^8)}{34.38 	imes 10^{-3} 	imes 0.04}$.$s = \frac{5.73 	imes 19.2 	imes 10^{-12} 	imes 175 	imes 10^8}{34.38 	imes 10^{-3} 	imes 0.04}$.$s = \frac{19249.92 	imes 10^{-4}}{1.3752 	imes 10^{-3}} \approx 1400 \ J \ kg^{-1} \ K^{-1}$.

Similar Questions

Which of the following is a part of the midbrain of a rabbit?

Which of the following does not define the functions and characteristics of plants?

Removal of shoot tips is a very useful technique to boost the production of tea-leaves. This is because

If $x^y \cdot y^x = 16$,then $\frac{dy}{dx}$ at $(2, 2)$ is

The oxygen evolved during photosynthesis comes from water molecules. Which one of the following pairs of elements is involved in this reaction?

Vedclass Test Series

Exam Paper Generator

Online Exam Module