A discrete random variable X has the distribu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For a binomial distribution $B(n, p)$,the variance is given by $\operatorname{Var}(X) = npq$,where $q = 1 - p$.Given $n = 15$ and $\operatorname{V

Vedclass · Accepted Answer

$0.3, 0.7$

Vedclass · Answer

(D) For a binomial distribution $B(n, p)$,the variance is given by $\operatorname{Var}(X) = npq$,where $q = 1 - p$.Given $n = 15$ and $\operatorname{Var}(X) = 3.15$.Substituting the values,we get $15 	imes p(1 - p) = 3.15$.Dividing by $15$,we get $p(1 - p) = \frac{3.15}{15} = 0.21$.This simplifies to $p - p^2 = 0.21$,or $p^2 - p + 0.21 = 0$.Solving the quadratic equation using the factorization method:$p^2 - 0.7p - 0.3p + 0.21 = 0$$p(p - 0.7) - 0.3(p - 0.7) = 0$$(p - 0.7)(p - 0.3) = 0$.Thus,the possible values for $p$ are $0.7$ and $0.3$.

$A$ discrete random variable $X$ has the distribution $B(15, p)$. Given that $\operatorname{Var}(X) = 3.15$. Then,the two possible values of $p$ are

Similar Questions

The random variable $X$ has a Binomial distribution $B(20, 0.4)$. Then $5 - 5 P(X \geq 2) =$

As a business strategy,$20 \%$ of the new internet service subscribers selected randomly receive a special promotion. If a group of $5$ such subscribers signs for the service,then the probability that at least two of them get the special promotion is

$A$ fair coin is tossed $100$ times. The chance of getting a head an even number of times is

It is given that the discrete random variable is $X \sim B(n, p)$ and $P(X=2)=P(X=3)$. Find the mean of the distribution.

$A$ person fails $4$ times in a game when he plays $9$ times. If he plays $15$ times,the probability of having success at most one is

Vedclass Test Series

Exam Paper Generator

Online Exam Module