A bag contains 21 toys numbered 1 to 21. A to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Total number of toys is $21$. The even numbers between $1$ and $21$ are $2, 4, 6, 8, 10, 12, 14, 16, 18, 20$. There are $10$ even numbers.Probabil

Vedclass · Accepted Answer

$\frac{3}{14}$

Vedclass · Answer

(B) Total number of toys is $21$. The even numbers between $1$ and $21$ are $2, 4, 6, 8, 10, 12, 14, 16, 18, 20$. There are $10$ even numbers.Probability of drawing the first even number is $\frac{10}{21}$.After drawing one even number,there are $9$ even numbers left out of $20$ total toys.Probability of drawing the second even number is $\frac{9}{20}$.The probability that both toys show even numbers is $\frac{10}{21} 	imes \frac{9}{20} = \frac{90}{420} = \frac{3}{14}$.

$A$ bag contains $21$ toys numbered $1$ to $21$. $A$ toy is drawn and then another toy is drawn without replacement. The probability that both toys will show even numbers is

Similar Questions

$A$ five-digit number is formed using the digits $1, 2, 3, 4, 5$ without repetition. What is the probability that the number is divisible by $4$?

$A$ bag contains $5$ red and $4$ green balls. If four balls are drawn at random,what is the probability that two balls are red and two balls are green?

$A$ group of $3$ is selected at random from $3$ men,$2$ women,and $4$ children. What is the probability that the group contains exactly $2$ children?

If two numbers are selected at random from $20$ consecutive integers,what is the probability that their sum is odd?

Five horses are in a race. $Mr. A$ selects two of the horses at random and bets on them. The probability that $Mr. A$ selected the winning horse is

Vedclass Test Series

Exam Paper Generator

Online Exam Module