int left(1 + frac{x}{1!} + frac{x^2}{2!} + do | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know that the Taylor series expansion for the exponential function $e^x$ is given by: $e^x = 1 + \frac{x}{1!} + \frac{x^2}{2!} + \frac{x^3}{3!}

Vedclass · Accepted Answer

$e^x + c$

Vedclass · Answer

(A) We know that the Taylor series expansion for the exponential function $e^x$ is given by: $e^x = 1 + \frac{x}{1!} + \frac{x^2}{2!} + \frac{x^3}{3!} + \dots \infty$ Substituting this into the integral,we get: $\int \left(1 + \frac{x}{1!} + \frac{x^2}{2!} + \dots \infty \right) dx = \int e^x dx$ The integral of $e^x$ with respect to $x$ is $e^x + c$,where $c$ is the constant of integration. Therefore,the final answer is $e^x + c$.

$\int \left(1 + \frac{x}{1!} + \frac{x^2}{2!} + \dots \infty \right) dx = $

Similar Questions

$\int {\frac{{1 + {{\cos }^2}x}}{{{{\sin }^2}x}}} \,dx = $

$\int \frac{d x}{x^{2}+2 x+2}$ equals

Find the integral of the function $\frac{\sin ^{2} x}{1+\cos x}$.

If $\int \frac{f(x) \, dx}{\log \sin x} = \log \log \sin x$,then $f(x) = $

$\int \sqrt{5-2x+x^2} dx$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module