operatorname{Tanh}^{-1}(sin theta) = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) माना कि $x = \operatorname{Tanh}^{-1}(\sin 	heta)$.तब $	anh x = \sin 	heta$.हम जानते हैं कि $\operatorname{sech}^2 x = 1 - 	anh^2 x = 1 - \sin

Vedclass · Accepted Answer

$\operatorname{Cosh}^{-1}(\sec 	heta)$

Vedclass · Answer

(D) माना कि $x = \operatorname{Tanh}^{-1}(\sin 	heta)$.तब $	anh x = \sin 	heta$.हम जानते हैं कि $\operatorname{sech}^2 x = 1 - 	anh^2 x = 1 - \sin^2 	heta = \cos^2 	heta$.अतः,$\operatorname{sech} x = \cos 	heta$,जिसका अर्थ है कि $\cosh x = \sec 	heta$.इसलिए,$x = \operatorname{Cosh}^{-1}(\sec 	heta)$.अतः,$\operatorname{Tanh}^{-1}(\sin 	heta) = \operatorname{Cosh}^{-1}(\sec 	heta)$.

$\operatorname{Tanh}^{-1}(\sin \theta) =$

Similar Questions

$\cos 1^\circ + \cos 2^\circ + \cos 3^\circ + \dots + \cos 180^\circ = $

$\cot (45^\circ + \theta ) \cot (45^\circ - \theta ) = $

$\frac{1-2(\cos 60^{\circ}-\cos 80^{\circ})}{2 \sin 10^{\circ}} = \dots$

यदि $\operatorname{cosech} x = \frac{4}{5}$ है,तो $\sinh x = $

$(\sin 210^{\circ})(\sin 585^{\circ})$ का मान क्या है?

Vedclass Test Series

Exam Paper Generator

Online Exam Module