$1+\cos 10^{\circ}+\cos 20^{\circ}+\cos 30^{\circ}=$

  • A
    $4 \sin 10^{\circ} \sin 20^{\circ} \sin 30^{\circ}$
  • B
    $4 \cos 5^{\circ} \cos 10^{\circ} \cos 15^{\circ}$
  • C
    $4 \cos 10^{\circ} \cos 20^{\circ} \cos 30^{\circ}$
  • D
    $4 \sin 5^{\circ} \sin 10^{\circ} \sin 15^{\circ}$

Explore More

Similar Questions

In an isosceles right-angled triangle,a straight line is drawn from the midpoint of one of the equal sides to the opposite vertex. Then a pair of possible values of the cotangents of the two angles so formed at that vertex are

Find the value of: $\tan 15^{\circ}$

If $A = \frac{\pi}{24}$,then $\frac{\cos A + \cos 3A + \cos 5A + \cos 7A}{\sin A + \sin 3A + \sin 5A + \sin 7A} = $

If $\cos \alpha + \cos \beta = \frac{1}{3}$ and $\sin \alpha + \sin \beta = \frac{1}{4}$,then $\cos (\alpha + \beta) = $

The value of $\tan \frac{2\pi}{5} - \tan \frac{\pi}{15} - \sqrt{3} \tan \frac{2\pi}{5} \tan \frac{\pi}{15}$ is equal to

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo