A projectile is thrown with a velocity of 10 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The initial velocity is $u = 10\sqrt{2} \ m/s$ at $	heta = 45^{\circ}$.The horizontal component is $u_x = u \cos 45^{\circ} = 10\sqrt{2} 	imes \

Vedclass · Accepted Answer

$1.0$

Vedclass · Answer

(D) The initial velocity is $u = 10\sqrt{2} \ m/s$ at $	heta = 45^{\circ}$.The horizontal component is $u_x = u \cos 45^{\circ} = 10\sqrt{2} 	imes \frac{1}{\sqrt{2}} = 10 \ m/s$.The vertical component is $u_y = u \sin 45^{\circ} = 10\sqrt{2} 	imes \frac{1}{\sqrt{2}} = 10 \ m/s$.At any time $t$,the velocity components are $v_x = 10 \ m/s$ and $v_y = 10 - 10t$.The speed $v$ is given by $v^2 = v_x^2 + v_y^2$.Given $v = \sqrt{125} \ m/s$,so $v^2 = 125$.$125 = 10^2 + (10 - 10t)^2$.$125 = 100 + (10 - 10t)^2$.$(10 - 10t)^2 = 25$.Taking the square root,$10 - 10t = \pm 5$.Case $1$: $10 - 10t = 5 \implies 10t = 5 \implies t_1 = 0.5 \ s$.Case $2$: $10 - 10t = -5 \implies 10t = 15 \implies t_2 = 1.5 \ s$.The time interval is $\Delta t = t_2 - t_1 = 1.5 - 0.5 = 1.0 \ s$.

Column $I$	Column $II$
$(A)$ Horizontal component of velocity	$(p)$ $5$ $SI$ unit
$(B)$ Vertical component of velocity	$(q)$ $10$ $SI$ unit
$(C)$ Horizontal displacement	$(r)$ $15$ $SI$ unit
$(D)$ Vertical displacement	$(s)$ $20$ $SI$ unit

$A$ projectile is thrown with a velocity of $10 \sqrt{2} \ m/s$ at an angle of $45^{\circ}$ with the horizontal. The time interval between the moments when the speed is $\sqrt{125} \ m/s$ is $(g = 10 \ m/s^2)$. (in $s$)

Similar Questions

An object is projected at an angle of $45^\circ$ with the horizontal. The ratio of the horizontal range to the maximum height reached is:

$A$ projectile is thrown with an initial velocity of $10 \ m/s$ at an angle $\alpha$ with the horizontal. It has a range of $5 \ m$. Taking $g = 10 \ m/s^2$ and neglecting air resistance,what will be the estimated value of $\alpha$ (in $^{\circ}$)?

$A$ football player throws a ball with a velocity of $50 \ m/s$ at an angle of $30^{\circ}$ from the horizontal. The ball remains in the air for ...... $s$ $(g = 10 \ m/s^2)$.

$A$ particle having kinetic energy $K$ is projected at $60^{\circ}$ with the horizontal. The kinetic energy at the highest point is

Vedclass Test Series

Exam Paper Generator

Online Exam Module