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(D) The range of the projectile is given as $R = 90 \,m$.The formula for the range of a projectile is $R = \frac{u^2 \sin(2	heta)}{g}$.To hit a targe

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$30$

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(D) The range of the projectile is given as $R = 90 \,m$.The formula for the range of a projectile is $R = \frac{u^2 \sin(2	heta)}{g}$.To hit a target at a fixed distance with the minimum initial velocity $u$, the range must be the maximum possible range for that velocity, which occurs at an angle of projection $	heta = 45^{\circ}$.Substituting $	heta = 45^{\circ}$ into the range formula: $R = \frac{u^2 \sin(90^{\circ})}{g} = \frac{u^2}{g}$.Given $R = 90 \,m$ and $g = 10 \,ms^{-2}$, we have $90 = \frac{u^2}{10}$.Therefore, $u^2 = 900$, which gives $u = 30 \,ms^{-1}$.

$A$ projectile is launched from the ground, such that it hits a target on the ground which is $90 \,m$ away. The minimum velocity of the projectile to hit the target is (acceleration due to gravity $= 10 \,ms^{-2}$) (in $\,ms^{-1}$)

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