A projectile is thrown with a velocity of 50 | vedclass

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Question

(D) Given: Initial velocity $u = 50 \, ms^{-1}$,angle $	heta = 53^o$.Horizontal component of velocity: $u_x = u \cos 53^o = 50 	imes (3/5) = 30 \, m

Vedclass · Accepted Answer

None of these.

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(D) Given: Initial velocity $u = 50 \, ms^{-1}$,angle $	heta = 53^o$.Horizontal component of velocity: $u_x = u \cos 53^o = 50 	imes (3/5) = 30 \, ms^{-1}$.Vertical component of velocity: $u_y = u \sin 53^o = 50 	imes (4/5) = 40 \, ms^{-1}$.Statement $A$: The vertical component of velocity at the start is $40 \, ms^{-1}$. This is correct.Statement $B$: The horizontal component of velocity is $30 \, ms^{-1}$. This is correct.Statement $C$: The minimum velocity of a projectile occurs at the highest point,which is equal to the horizontal component $u_x = 30 \, ms^{-1}$. This is correct.Since all statements $A, B,$ and $C$ are correct,the incorrect statement is none of these.

$P$. Time of flight	$1$. $3$
$Q$. Time when particle is moving at an angle of $53^{\circ}$ with horizontal in upwards direction.	$2$. $10$
$R$. Range of the particle	$3$. $50$
$S$. Maximum height reached by the particle	$4$. $60$

$A$ projectile is thrown with a velocity of $50 \, ms^{-1}$ at an angle of $53^o$ with the horizontal. Choose the incorrect statement.

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