A force F is needed to break a copper wire ha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The breaking force of a wire is determined by its breaking stress,which is a material property. The breaking force $F$ is given by the product of

Vedclass · Accepted Answer

$4F$

Vedclass · Answer

(C) The breaking force of a wire is determined by its breaking stress,which is a material property. The breaking force $F$ is given by the product of breaking stress $\sigma$ and the cross-sectional area $A$ of the wire.$F = \sigma 	imes A = \sigma 	imes (\pi R^2)$Since the material is the same (copper),the breaking stress $\sigma$ remains constant.Therefore,$F \propto R^2$.If $F_1 = F$ for radius $R_1 = R$,and $F_2$ is the force for radius $R_2 = 2R$,then:$\frac{F_2}{F_1} = \left(\frac{R_2}{R_1}ight)^2 = \left(\frac{2R}{R}ight)^2 = 4$$F_2 = 4F_1 = 4F$.

Column-$I$	Column-$II$
$(a)$ Stress is proportional to strain.	$(i)$ Elastic limit
$(b)$ When the load on the wire is removed, the body regains its original dimension.	$(ii)$ Limit of proportionality
	$(iii)$ Plastic deformation

$A$ force $F$ is needed to break a copper wire having radius $R$. The force needed to break a copper wire of radius $2R$ will be

Similar Questions

The elastic limit for a gas

The spring balance does not read properly after its long use,because

Hooke's law defines:

The load versus elongation graph for four wires of same length and the same material is shown in the figure. The thinnest wire is represented by the line:

Vedclass Test Series

Exam Paper Generator

Online Exam Module