(D) The magnetic field produced by the long straight wire is perpendicular to the plane of the rectangular loop at all points. According to the right-

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(D) The magnetic field produced by the long straight wire is perpendicular to the plane of the rectangular loop at all points. According to the right-hand rule,the magnetic force on each of the four sides of the loop lies within the plane of the loop itself. Since all the forces acting on the sides of the loop are coplanar and their lines of action pass through the plane of the loop,the net torque about any axis in the plane of the loop is zero. Therefore,the net torque acting on the loop is $0$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

$A$ current-carrying rectangular loop is placed near a straight infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

AP EAMCET 2018 All AP EAMCET

A
$\frac{\mu_0}{2 \pi} \frac{i_1 i_2 l}{a b}$
B
$\frac{\mu_0}{2 \pi} \frac{i_1 i_2 l}{a(a+b)}$
C
$\frac{\mu_0}{2 \pi} \frac{i_1 i_2 l(b-a)}{a b}$
D
$0$

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$A$ current-carrying rectangular loop is placed near a straight infinitely long current-carrying wire as shown in the figure. The torque acting on the loop is

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In a transformer,the number of turns in the primary coil is $140$ and that in the secondary coil is $280$. If the current in the primary coil is $4 \, A$,then the current in the secondary coil is.....$A$.

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