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(A) The average kinetic energy of a gas molecule is given by the formula $KE_{av} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ i

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(A) The average kinetic energy of a gas molecule is given by the formula $KE_{av} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature of the gas.Since the argon and chlorine gases are in the same flask and in thermal equilibrium,they are at the same temperature $T = 27^{\circ} C = 300 \ K$.Because the average kinetic energy per molecule depends only on the temperature $T$ and is independent of the mass or the nature of the gas molecules,the ratio of the average kinetic energies of the two gases is $1:1$.

$A$ flask contains argon and chlorine in the ratio of $2:1$ by mass. The temperature of the mixture is $27^{\circ} C$. The ratio of average kinetic energies of two gases per molecule is (in $:1$)

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