Propyne xrightarrow[Hg^{2+} / H_2 O, Delta]{H | vedclass

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(C) $1$. $Propyne$ $(CH_3-C \equiv CH)$ reacts with $Hg^{2 } / H_2O, H $ to undergo hydration to form $Acetone$ $(CH_3-CO-CH_3)$ as $P$.
$2$. $Aceton

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(C) $1$. $Propyne$ $(CH_3-C \equiv CH)$ reacts with $Hg^{2 } / H_2O, H $ to undergo hydration to form $Acetone$ $(CH_3-CO-CH_3)$ as $P$.
$2$. $Acetone$ $(P)$ undergoes $Aldol$ condensation in the presence of $Ba(OH)_2$ to form $Diacetone$ $alcohol$ $(Q)$,which is $CH_3-CO-CH_2-C(OH)(CH_3)_2$.
$3$. Upon heating $(\Delta)$,$Diacetone$ $alcohol$ $(Q)$ undergoes dehydration to form $Mesityl$ $oxide$ $(R)$,which is $CH_3-CO-CH=C(CH_3)_2$.

$Propyne$ $\xrightarrow[Hg^{2+} / H_2 O, \Delta]{H^{+}}$ $P$ $\stackrel{Ba(OH)_2}{\rightleftharpoons}$ $Q$ $\xrightarrow{\Delta}$ $R$. $R$ in the above sequence of reactions is:

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