$1 + \cot^2(\sin^{-1}x) = $

  • A
    $\frac{1}{2x}$
  • B
    $x^2$
  • C
    $\frac{1}{x^2}$
  • D
    $\frac{2}{x}$

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$\sin (\cot ^{ - 1}x) = $

Consider the following statements:
Statement-$I$: $\operatorname{Cosh}^{-1} x = \operatorname{Tanh}^{-1} x$ has no solution.
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The correct answer is:

The principal value of $\cot ^{-1}\left(\frac{-1}{\sqrt{3}}\right)$ is

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