Easy
$A$ resistor of resistance $R$, an inductor of inductive reactance $2R$, and a capacitor of capacitive reactance $X_C$ are connected in series to an $A.C.$ source. If the series $LCR$ circuit is in resonance, then the power factor of the circuit and the value $X_C$ are respectively:
- A$0.5$ and $4R$
- B$1$ and $2R$
- C$0.5$ and $2R$
- D$1$ and $4R$
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Similar Questions
The resonant frequency of a series $LCR$ circuit is $f_R$. The circuit is connected to a sinusoidally alternating e.m.f. of frequency $2 f_R$. The inductive reactance becomes $X_{L_1}$ and capacitive reactance becomes $X_{C_1}$ after changing the frequency. $X_{C_1}$ is equal to:
In a series $LCR$ circuit,the inductance $L$ is $10\,mH$,capacitance $C$ is $1\,\mu F$ and resistance $R$ is $100\,\Omega$. The frequency at which resonance occurs is:
Power delivered by the $ac$ source of the circuit becomes maximum when
Medium
View SolutionWhat is the value of inductance $L$ for which the current is a maximum in a series $LCR$ circuit with $C=10 \mu F$ and $\omega=1000 \ s^{-1}$?
DifficultMHT CET 2008
View Solution$A$ series $LCR$ circuit is connected to an ac voltage source. When $L$ is removed from the circuit,the phase difference between current and voltage is $\frac{\pi}{3}$. If instead $C$ is removed from the circuit,the phase difference is again $\frac{\pi}{3}$ between current and voltage. The power factor of the circuit is:
MediumAIPMT 2012
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