A carbonyl compound X (C_8H_8O) gives a yello | vedclass

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(C) The carbonyl compound $X$ has the molecular formula $C_8H_8O$. Since it gives a yellow precipitate with $NaOI$ (iodoform test),it must contain a $

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(C) The carbonyl compound $X$ has the molecular formula $C_8H_8O$. Since it gives a yellow precipitate with $NaOI$ (iodoform test),it must contain a $CH_3CO-$ group or a $CH_3CH(OH)-$ group. Given it is a carbonyl compound,it must be acetophenone $(C_6H_5COCH_3)$. When acetophenone reacts with methanol $(CH_3OH)$ in the presence of dry $HCl$,it forms a hemiacetal. The reaction is: $C_6H_5COCH_3 + CH_3OH \xrightarrow{dry \ HCl} C_6H_5C(OH)(OCH_3)CH_3$. Comparing this with the given options,the structure in option $C$ represents the hemiacetal $1$-methoxy-$1$-phenylethanol.

$A$ carbonyl compound $X$ $(C_8H_8O)$ gives a yellow precipitate with $NaOI$. The hemiacetal of $X$ with methanol/dry $HCl$ is:

Similar Questions

Identify the products $(A)$ and $(C)$ in the following reaction sequence:
$Cyclopentyl-^{14}CN + CH_3MgBr$ $\xrightarrow{H_3O^\oplus} (A)$ $\xrightarrow{NaOI} (B) + (C)$

Reduction of $>C=O$ to $CH_2$ can be carried out with:

The following reaction gives:

Which of the following compounds is a hemiacetal?

What are $X$ and $Y$ respectively in the following reactions?
$C_6H_5COOH \xrightarrow{X} C_6H_5CHO$
$C_6H_5CHO \xrightarrow[OH^-, 293 \ K]{C_6H_5COOH} Y \text{ (Major product)}$

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