The following reaction gives:

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(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.I

Vedclass · Accepted Answer

$3,4-$Dimethoxybenzyl alcohol + Formate ion

Vedclass · Answer

(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.In a Cross Cannizzaro reaction,the more reactive aldehyde (formaldehyde) is oxidized to the corresponding acid salt (formate,$HCOO^-$),and the less reactive aldehyde ($3$,$4$-dimethoxybenzaldehyde) is reduced to the corresponding alcohol ($3$,$4$-dimethoxybenzyl alcohol).Therefore,the products are $3,4-$dimethoxybenzyl alcohol and the formate ion $(HCOO^-)$.

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