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(B) ray of light incident normally on one face of a right-angled isosceles prism passes undeviated into the prism.When it reaches the hypotenuse,the a

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$1.414$

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(B) ray of light incident normally on one face of a right-angled isosceles prism passes undeviated into the prism.When it reaches the hypotenuse,the angle of incidence $i$ is $45^{\circ}$.Since the ray grazes the hypotenuse,the angle of refraction is $90^{\circ}$.Thus,the angle of incidence is equal to the critical angle $C$,so $C = 45^{\circ}$.The refractive index $\mu$ is given by $\mu = \frac{1}{\sin C}$.Substituting the value of $C$,we get $\mu = \frac{1}{\sin 45^{\circ}} = \frac{1}{1/\sqrt{2}} = \sqrt{2}$.Therefore,$\mu \approx 1.414$.

$A$ ray of light is incident normally on one face of a right-angled isosceles prism. It then grazes the hypotenuse. The refractive index of the material of the prism is

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