An optical fiber works on the principle of ......

  • A
    Total internal reflection
  • B
    Reflection
  • C
    Refraction
  • D
    Dispersion

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Similar Questions

An optical fibre consists of a core of refractive index $\mu_1$ surrounded by a cladding of refractive index $\mu_2 < \mu_1$. $A$ beam of light enters from air at an angle $\alpha$ with the axis of the fibre. The highest angle $\alpha$ for which the ray can travel through the fibre is:

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Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $\theta$. If a ray of light is incident from air on the glass with angle of incidence $\theta$,the corresponding angle of refraction is:

White light is incident on the interface of glass and air as shown in the figure. If green light is just totally internally reflected,then the reflected rays inside the glass contain:

Assertion: The air bubble shines in water.
Reason: Air bubble in water shines due to refraction of light.

$A$ light ray is incident normally on one face of a right-angled prism and travels parallel to the base inside the prism. If the refractive index of the prism is $\mu$,what should be the angle $\alpha$ that the hypotenuse makes with the base so that the ray undergoes total internal reflection at the hypotenuse?

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