$A$ plane electromagnetic wave of frequency $20 \text{ MHz}$ travels through space along the $x$-direction. If the electric field vector at a certain point in space is $6 \text{ V m}^{-1}$,what is the magnetic field vector at that point?

An electron is constrained to move along the $y$-axis with a speed of $0.1 c$ ($c$ is the speed of light) in the presence of an electromagnetic wave,whose electric field is $\overrightarrow{E} = 30 \hat{j} \sin(1.5 \times 10^7 t - 5 \times 10^{-2} x) \, V/m$. The maximum magnetic force experienced by the electron will be: (given $c = 3 \times 10^8 \, m/s$ and electron charge $q = 1.6 \times 10^{-19} \, C$)

For plane electromagnetic waves propagating in the positive $Z$-direction,the combination which gives the correct possible direction for $\vec{E}$ and $\vec{B}$ fields respectively is:

The rms value of the electric field of an electromagnetic wave emitted by a source is $660 \ NC^{-1}$. The average energy density of the electromagnetic wave is

The average value of electric energy density in an electromagnetic wave is. [where $E_0$ is peak value]

The relation between the permittivity of free space $(\epsilon_0)$, the permeability of free space $(\mu_0)$, and the speed of light $(c)$ is: