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(D) The magnetic field inside a long current-carrying solenoid is uniform and directed along its axis.When a charged particle (proton) is projected wi

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the proton will continue to move with velocity $v$ along the axis,

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(D) The magnetic field inside a long current-carrying solenoid is uniform and directed along its axis.When a charged particle (proton) is projected with a velocity $v$ parallel to the magnetic field $B$,the magnetic force $F_m$ acting on it is given by the Lorentz force formula: $F_m = q(v 	imes B)$.Since the velocity vector $v$ is parallel to the magnetic field vector $B$,the angle $	heta$ between them is $0^\circ$.Therefore,the magnetic force $F_m = qvB \sin(0^\circ) = 0$.As there is no magnetic force acting on the proton,it will experience no acceleration and will continue to move with the same uniform velocity $v$ along the axis of the solenoid.

$A$ proton is projected with a uniform velocity $v$ along the axis of a current-carrying solenoid,then

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