$ABC$ is a triangle with $\angle A=30^{\circ}$ and $BC=10 \text{ cm}$. The area of the circumcircle of the triangle is
- A$100 \pi \text{ cm}^2$
- B$5 \text{ cm}^2$
- C$25 \text{ cm}^2$
- D$\frac{100 \pi}{3} \text{ cm}^2$
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If the lengths of the sides of a triangle are $3, 4$ and $5$ units,then $R$ (the circumradius) is ............ $unit$.
Medium
View SolutionThe sides of a right-angled triangle are integers. The length of one of the sides is $12$. The largest possible radius of the incircle of such a triangle is
In a $\triangle ABC$,if $a=13, b=14, c=15$,then find the value of $r_1$.
In $\triangle ABC$,with usual notation,observe the two statements given below :
$(I)$ $r r_1 r_2 r_3 = \Delta^2$
$(II)$ $r_1 r_2 + r_2 r_3 + r_3 r_1 = s^2$
Which of the following is correct?
$(I)$ $r r_1 r_2 r_3 = \Delta^2$
$(II)$ $r_1 r_2 + r_2 r_3 + r_3 r_1 = s^2$
Which of the following is correct?
In a right $\triangle ABC$,the incircle touches the hypotenuse $AC$ at $D$. If $AD=10$ and $DC=3$,the inradius of $\triangle ABC$ is
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