The resistance of a galvanometer is $90\, \Omega$. If only $10\%$ of the main current is to flow through the galvanometer,how should a resistor be connected and what should be its value?

  • A
    $10\, \Omega$ in series
  • B
    $10\, \Omega$ in parallel
  • C
    $810\, \Omega$ in series
  • D
    $810\, \Omega$ in parallel

Explore More

Similar Questions

$A$ galvanometer of resistance $G$ has a voltage range $V_g$. The resistance required to convert it to read voltage up to $V$ is

To make the magnetic field radial in a moving coil galvanometer:

Match the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:
List-$I$ List-$II$
$A$. Figure of merit $(k)$ $P$. in series
$B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized
$C$. Deflection is made half by using low resistance $R$. in shunt/parallel
$D$. High resistance box $S$. current per unit deflection
$T$. deflection per unit current

When a shunt of $4\,\Omega$ is connected to a galvanometer,the deflection reduces to $1/5$ of its initial value. If an additional shunt of $2\,\Omega$ is connected in parallel,what will be the new deflection?

The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo