$A$ cyclotron is used to accelerate

In a cyclotron,a charged particle:

An alternating electric field of frequency $f$ is applied across the radius $R$ of a cyclotron to accelerate protons (mass $m$). The operating magnetic field $B$ used and kinetic energy $(K.E.)$ of the proton beam produced by it are respectively ($e=$ charge on proton).

$A$ cyclotron is used to accelerate protons $\left({ }_{1}^{1} H\right)$,deuterons $\left({ }_{1}^{2} H\right)$,and $\alpha$-particles $\left({ }_{2}^{4} He\right)$. While exiting under similar conditions,the minimum kinetic energy $(KE)$ is gained by:

$A$ cyclotron is used to accelerate protons. If the operating magnetic field is $1.0\,T$ and the radius of the cyclotron 'dees' is $60\,cm$,the kinetic energy of the accelerated protons in $MeV$ will be.
[use $m_{p} = 1.6 \times 10^{-27}\,kg, e = 1.6 \times 10^{-19}\,C$]

The oscillating frequency of a cyclotron is $10 \, MHz$. If the radius of its dee is $0.5 \, m$,the kinetic energy of a proton,which is accelerated by the cyclotron,is ...... $MeV$.