5.5 text{ mg} of nitrogen gas dissolves in 18 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Moles of $N_2 = \frac{5.5 	imes 10^{-3} 	ext{ g}}{28 	ext{ g/mol}} \approx 1.96 	imes 10^{-4} 	ext{ mol}$.Moles of $H_2O = \frac{180 	ext{ g

Vedclass · Accepted Answer

$1 	imes 10^{-4}$

Vedclass · Answer

(B) Moles of $N_2 = \frac{5.5 	imes 10^{-3} 	ext{ g}}{28 	ext{ g/mol}} \approx 1.96 	imes 10^{-4} 	ext{ mol}$.Moles of $H_2O = \frac{180 	ext{ g}}{18 	ext{ g/mol}} = 10 	ext{ mol}$.Mole fraction of $N_2$ at $1 	ext{ atm}$ $(x_1)$ = $\frac{n_{N_2}}{n_{H_2O} + n_{N_2}} \approx \frac{1.96 	imes 10^{-4}}{10} = 1.96 	imes 10^{-5}$.According to Henry's law,$p = K_H \cdot x$,which implies $x \propto p$.At $5 	ext{ atm}$ pressure,the new mole fraction $(x_2)$ is $x_2 = 5 	imes x_1 = 5 	imes 1.96 	imes 10^{-5} = 9.8 	imes 10^{-5} \approx 1 	imes 10^{-4}$.

$5.5 \text{ mg}$ of nitrogen gas dissolves in $180 \text{ g}$ of water at $273 \text{ K}$ and $1 \text{ atm}$ pressure due to nitrogen gas. The mole fraction of nitrogen in $180 \text{ g}$ of water at $5 \text{ atm}$ nitrogen pressure is approximately:

Similar Questions

Consider a solution of $CO_{2(g)}$ dissolved in water in a closed container. Which one of the following plots correctly represents the variation of $log$ (partial pressure of $CO_2$ in vapour phase above water) [y-axis] with $log$ (mole fraction of $CO_2$ in water) [x-axis] at $25^{\circ}C$?

As temperature increases,the value of $K_H$ increases,thus the value of solubility of a gaseous solute will $ . . . . . . $.

Henry's law constant for the molality of methane in benzene at $298 \, K$ is $4.27 \times 10^{5} \, mm \, Hg$. Calculate the solubility of methane in benzene at $298 \, K$ under $760 \, mm \, Hg$.

How many millimoles of nitrogen dissolve when nitrogen is passed in $1 \ L$ water at $293 \ K$ temperature? $[$ The value of $K_H$ is $7.648 \times 10^4 \ bar$ and partial pressure of $N_2$ gas is $0.987 \ bar.]$

Solubility of $N_2$ gas in water at $25\,^{\circ}C$ and $0.78\, atm$ is $5.4 \times 10^{-4}\, M$. Calculate Henry's law constant for $N_2$ in water at $25\,^{\circ}C$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module