$\tan 5x \tan 3x \tan 2x = $

  • A
    $\tan 5x - \tan 3x - \tan 2x$
  • B
    $\frac{\sin 5x - \sin 3x - \sin 2x}{\cos 5x - \cos 3x - \cos 2x}$
  • C
    $0$
  • D
    इनमें से कोई नहीं

Explore More

Similar Questions

मान लीजिए $\tan \alpha = \frac{a}{a+1}$ और $\tan \beta = \frac{1}{2a+1}$,तो $\alpha + \beta$ का मान क्या है?

यदि $\tan \theta = \frac{\sin \alpha - \cos \alpha}{\sin \alpha + \cos \alpha}$ और $0 \leq \alpha \leq \frac{\pi}{2}$ है,तो $\cos 2 \theta$ का मान क्या है?

$\frac{\tan 52^{\circ} - \tan 38^{\circ}}{\tan 14^{\circ}} = $

$\tan 75^\circ - \cot 75^\circ = $

यदि $\tan \alpha = \frac{m}{m + 1}$ और $\tan \beta = \frac{1}{2m + 1}$ है,तो $\alpha + \beta = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo