At the first minimum adjacent to the central maximum of a single-slit diffraction pattern,the phase difference between the Huygens' wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

  • A
    $\frac{\pi}{8} \text{ rad}$
  • B
    $\frac{\pi}{4} \text{ rad}$
  • C
    $\frac{\pi}{2} \text{ rad}$
  • D
    $\pi \text{ rad}$

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$A$ circular disc is placed in front of a narrow source. When the point of observation is $2 \, m$ from the disc,it covers the first $HPZ$. The intensity at this point is $I$. When the point of observation is $25 \, cm$ from the disc,the intensity will be:

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In a Fraunhofer diffraction due to a single slit,the diffraction pattern is formed on the focal plane of a lens of focal length $f = 1 \ m$. The width of the slit is $a = 0.3 \ mm$. If the third minimum is formed at a distance of $5 \ mm$ from the central maximum,find the wavelength of light in $\mathring{A}$.

$A$ single slit diffraction pattern is formed with light of wavelength $6384 Å$. The second secondary maximum for this wavelength coincides with the third secondary maximum in the pattern for light of wavelength $\lambda_0$. The value of $\lambda_0$ is (in $Å$)

$A$ screen is placed at a distance $50\,cm$ from a single slit,which is illuminated with light of wavelength $690\,nm$. If the distance between the first and third minima is $3.00\,mm$,what is the width of the slit (in $,mm$)?

In the far-field diffraction pattern of a single slit under polychromatic illumination,the first minimum with the wavelength ${\lambda _1}$ is found to be coincident with the third maximum at ${\lambda _2}$. So,

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