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(C) For a thin prism with a small angle '$A$',the relationship between the angle of incidence '$i$',the angle of refraction '$r_1$',and the angle of e

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$\mu A$

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(C) For a thin prism with a small angle '$A$',the relationship between the angle of incidence '$i$',the angle of refraction '$r_1$',and the angle of emergence '$r_2$' is given by $A = r_1 + r_2$.Since the ray emerges normally from the opposite surface,the angle of emergence is $0$,which implies $r_2 = 0$.Therefore,$A = r_1 + 0$,so $r_1 = A$.According to Snell's Law,$\mu = \frac{\sin i}{\sin r_1}$. For small angles,$\sin i \approx i$ and $\sin r_1 \approx r_1$.Thus,$\mu = \frac{i}{r_1}$.Substituting $r_1 = A$,we get $\mu = \frac{i}{A}$,which simplifies to $i = \mu A$.

$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a thin prism of small angle '$A$'. The ray emerges normally from the opposite surface. If the refractive index of the material of the prism is '$\mu$',the angle of incidence '$i$' is nearly equal to

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