$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a prism of small angle '$A$' and emerges normally from the other surface. If the refractive index of the material of the prism is '$\mu$',then the angle of incidence is equal to

The refractive index of the material of a prism is $\sqrt{2}$ and the angle of the prism is $30^{\circ}$. One of the two refracting surfaces of the prism is made a mirror inwards,by silver coating. $A$ beam of monochromatic light entering the prism from the other face will retrace its path (after reflection from the silvered surface) if its angle of incidence on the prism is (in $^{\circ}$)

In the given figure,what is the angle of the prism?

For a prism of refractive index $1.732$,the angle of minimum deviation is equal to the angle of the prism. The angle of the prism is......$^o$

$A$ prism $(\mu = 1.5)$ has a refracting angle of $30^\circ$. The deviation of a monochromatic ray incident normally on one of its surfaces will be $(\sin 48^\circ 36' = 0.75)$.

One face of a glass prism is silver-polished. $A$ light ray falls at an angle of $45^{\circ}$ on the other face. After refraction,it is subsequently reflected from the silvered face and then retraces its path. The refracting angle of the prism is $30^{\circ}$. The refractive index of the prism is: