$A$ convex lens of refractive index $\frac{3}{2}$ has a power of $2.5 \ D$. If it is placed in a liquid of refractive index $2$, the new power of the lens is: (in $D$)

  • A
    $2.5$
  • B
    $-2.5$
  • C
    $1.25$
  • D
    $-1.25$

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