A nucleus breaks into two nuclear parts,which | vedclass

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(C) By the law of conservation of momentum,the two parts will have equal and opposite momentum,assuming the nucleus was initially at rest.$m_1 v_1 = m

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$1/2^{1/3}$

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(C) By the law of conservation of momentum,the two parts will have equal and opposite momentum,assuming the nucleus was initially at rest.$m_1 v_1 = m_2 v_2$$\frac{m_1}{m_2} = \frac{v_2}{v_1} = \frac{1}{2}$Since the nuclear mass $m$ is proportional to the volume,which is proportional to the cube of the radius $r^3$ (i.e.,$m \propto r^3$):$\frac{m_1}{m_2} = \left(\frac{r_1}{r_2}\right)^3$Substituting the mass ratio:$\left(\frac{r_1}{r_2}\right)^3 = \frac{1}{2}$$\frac{r_1}{r_2} = \left(\frac{1}{2}\right)^{1/3} = \frac{1}{2^{1/3}}$

$A$ nucleus breaks into two nuclear parts,which have their velocity ratio $2:1$. The ratio of their nuclear radii will be

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