The value of the average density of a nucleus | vedclass

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Question

(B) The average density of a nucleus is approximately $ho_{n} = 2.3 	imes 10^{17} \ kg/m^{3}$.The density of water is $ho_{w} = 10^{3} \ kg/m^{3}

Vedclass · Accepted Answer

$2.3 	imes 10^{14}$

Vedclass · Answer

(B) The average density of a nucleus is approximately $ho_{n} = 2.3 	imes 10^{17} \ kg/m^{3}$.The density of water is $ho_{w} = 10^{3} \ kg/m^{3}$.To find the ratio,we divide the density of the nucleus by the density of water:$	ext{Ratio} = \frac{ho_{n}}{ho_{w}} = \frac{2.3 	imes 10^{17} \ kg/m^{3}}{10^{3} \ kg/m^{3}} = 2.3 	imes 10^{14}$.Therefore,the density of the nucleus is $2.3 	imes 10^{14}$ times that of water.

The value of the average density of a nucleus is $\qquad$ times that of water.

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