A solenoid having 400 turns per metre has a c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The magnetic intensity $H$ is given by $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.Given $n = 400 \ m^{-1}$ a

Vedclass · Accepted Answer

$8 	imes 10^4$

Vedclass · Answer

(D) The magnetic intensity $H$ is given by $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.Given $n = 400 \ m^{-1}$ and $I = 0.5 \ A$,we have $H = 400 	imes 0.5 = 200 \ Am^{-1}$.The relationship between relative permeability $\mu_r$ and magnetic susceptibility $\chi$ is $\mu_r = 1 + \chi$,so $\chi = \mu_r - 1$.Given $\mu_r = 400$,we find $\chi = 400 - 1 = 399$.The magnetization $M$ is given by $M = \chi H$.Substituting the values,$M = 399 	imes 200 = 79800 \ Am^{-1}$.This is approximately $8 	imes 10^4 \ Am^{-1}$.

$A$ solenoid having $400$ turns per metre has a core of a material with relative permeability $400$. When a current of $0.5 \ A$ is passed through it,the magnetization of the core material in $Am^{-1}$ is nearly

Similar Questions

$A$ solenoid has a core of material with relative permeability $501$. The windings of the solenoid are insulated from the core and carry a current of $2.5 \ A$. If the number of turns is $900$ per metre,the magnetization in $A \ m^{-1}$ is:

The magnetic susceptibility of a material is $7.54 \times 10^{-3}$. The nature and relative permeability of the substance are:

$A$ paramagnetic substance in the form of a cube with sides $1\, cm$ has a magnetic dipole moment of $20 \times 10^{-6}\, J/T$ when a magnetic intensity of $60 \times 10^3\, A/m$ is applied. Its magnetic susceptibility is

Oersted is a unit of

If the relative permeability of iron is $5500$,then its magnetic susceptibility is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module