A solenoid has a core of material with relati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetization $M$ is given by the formula $M = \chi H$,where $\chi$ is the magnetic susceptibility and $H$ is the magnetic field intensity.For

Vedclass · Accepted Answer

$1.125 	imes 10^6$

Vedclass · Answer

(A) The magnetization $M$ is given by the formula $M = \chi H$,where $\chi$ is the magnetic susceptibility and $H$ is the magnetic field intensity.For a solenoid,the magnetic field intensity is $H = nI$,where $n$ is the number of turns per unit length and $I$ is the current.The magnetic susceptibility is related to the relative permeability $\mu_r$ by the relation $\chi = \mu_r - 1$.Given: $n = 900 \ m^{-1}$,$I = 2.5 \ A$,and $\mu_r = 501$.Substituting these values into the formula $M = nI(\mu_r - 1)$:$M = 900 	imes 2.5 	imes (501 - 1)$$M = 2250 	imes 500$$M = 1,125,000 \ A \ m^{-1} = 1.125 	imes 10^6 \ A \ m^{-1}$.

$A$ solenoid has a core of material with relative permeability $501$. The windings of the solenoid are insulated from the core and carry a current of $2.5 \ A$. If the number of turns is $900$ per metre,the magnetization in $A \ m^{-1}$ is:

Similar Questions

An iron rod of cross-sectional area $0.2 \, cm^2$ is subjected to a magnetizing field intensity of $1600 \, A \cdot m^{-1}$. If the magnetic flux produced in the rod is $2.4 \times 10^{-5} \, Wb$, what is the magnetic susceptibility of the material of the rod?

The value of aluminium susceptibility is $2.2 \times 10^{-5}$. The percentage increase in the magnetic field if space within a current-carrying toroid is filled with aluminium is $\frac{x}{10^{4}}$. Then the value of $x$ is ...... .

An iron rod is placed parallel to a magnetic field of intensity $2000 \text{ A/m}$. The magnetic flux through the rod is $6 \times 10^{-4} \text{ Wb}$ and its cross-sectional area is $3 \text{ cm}^2$. The magnetic permeability of the rod in $\text{Wb/(A} \cdot \text{m)}$ is:

The unit for molar susceptibility is

The permeability of a metal is $0.1256 \ TmA^{-1}$. Its relative permeability will be (Given: $\frac{\mu_0}{4 \pi} = 10^{-7} \ SI \ unit$,$\pi = 3.14$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module