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(B) Magnetization $I$ (or $M$) is defined as the magnetic dipole moment per unit volume: $I = \frac{M_{dipole}}{V}$.Given:Mass $m = 1 \, g = 10^{-3} \

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(B) Magnetization $I$ (or $M$) is defined as the magnetic dipole moment per unit volume: $I = \frac{M_{dipole}}{V}$.Given:Mass $m = 1 \, g = 10^{-3} \, kg$.Density $ho = 5 \, g/cm^3 = 5000 \, kg/m^3 = 5 	imes 10^3 \, kg/m^3$.Magnetic dipole moment $M_{dipole} = 6 	imes 10^{-7} \, A \cdot m^2$.First,calculate the volume $V$:$V = \frac{m}{ho} = \frac{1 \, g}{5 \, g/cm^3} = 0.2 \, cm^3 = 0.2 	imes 10^{-6} \, m^3 = 2 	imes 10^{-7} \, m^3$.Now,calculate the magnetization $I$:$I = \frac{6 	imes 10^{-7} \, A \cdot m^2}{2 	imes 10^{-7} \, m^3} = 3 \, A/m$.

$A$ substance has a mass of $1 \, g$ and a density of $5 \, g/cm^3$. Its magnetic dipole moment is $6 \times 10^{-7} \, A \cdot m^2$. What is the magnetization in $A/m$?

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