$A$ massless square loop of wire of resistance $R$ supporting a mass $M$ hangs vertically with one of its sides in a uniform magnetic field $B$ directed outwards in the shaded region. $A$ d.c. voltage $V$ is applied to the loop. For what value of $V$ will the magnetic force exactly balance the weight of the supporting mass $M$? (side of loop $= L, g =$ acceleration due to gravity)
- A$\frac{Mg}{LBR}$
- B$\frac{LB}{MgR}$
- C$\frac{MgR}{LB}$
- D$\frac{LR}{MgB}$
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