Work done by air when it expands from 50 , L | vedclass

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Question

(A) The work done during an isobaric expansion is given by the formula $W = P \Delta V$.Given:Pressure $P = 2 \, atm = 2 	imes 1.013 	imes 10^5 \, P

Vedclass · Accepted Answer

$2 	imes 10^4 \, J$

Vedclass · Answer

(A) The work done during an isobaric expansion is given by the formula $W = P \Delta V$.Given:Pressure $P = 2 \, atm = 2 	imes 1.013 	imes 10^5 \, Pa \approx 2 	imes 10^5 \, Pa$.Initial volume $V_1 = 50 \, L = 50 	imes 10^{-3} \, m^3$.Final volume $V_2 = 150 \, L = 150 	imes 10^{-3} \, m^3$.Change in volume $\Delta V = V_2 - V_1 = (150 - 50) 	imes 10^{-3} \, m^3 = 100 	imes 10^{-3} \, m^3 = 0.1 \, m^3$.Substituting the values into the work formula:$W = (2 	imes 10^5 \, Pa) 	imes (0.1 \, m^3) = 2 	imes 10^4 \, J$.Thus,the correct option is $A$.

Work done by air when it expands from $50 \, L$ to $150 \, L$ at a constant pressure of $2 \, atm$ is:

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