A standing wave having 3 nodes and 2 antinode | vedclass

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(A) Key Idea: The standing wave has $3$ nodes $(N)$ and $2$ antinodes $(A)$,which means it consists of $2$ loops or segments.The distance between two

Vedclass · Accepted Answer

$1.21$

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(A) Key Idea: The standing wave has $3$ nodes $(N)$ and $2$ antinodes $(A)$,which means it consists of $2$ loops or segments.The distance between two consecutive nodes is $\frac{\lambda}{2}$.Since there are $3$ nodes,there are $2$ such segments between the two atoms.The total length $L$ of the standing wave is the sum of the lengths of these $2$ segments:$L = 2 	imes \left( \frac{\lambda}{2} ight) = \lambda$Given that the distance between the two atoms is $1.21 \ Å$,we have:$L = 1.21 \ Å$Therefore,$\lambda = 1.21 \ Å$.

$A$ standing wave having $3$ nodes and $2$ antinodes is formed between two atoms having a distance of $1.21 \ Å$ between them. The wavelength of the standing wave is (in $Å$)

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